1.1. Matter Stimulated Oscillation

We investigate a system with matter potential

λ(x)=λ0+δλ(x),

where λ0=2GFne0 and δλ(x)=2GFδne(x).

The Hamiltonian in background matter basis {|νL,|νH} is

H=ωm2σ3+δλ2cos2θmσ3δλ2sin2θmσ1.

Here by background matter basis, we mean that the Hamiltonian is diagonalized if perturbation is zero in matter profile.

Derive the Hamiltonian

This Hamiltonian can be derived easily using

H=ωm3σ3+δλ2Uσ3U.

What we are interested in is the transition between two background mass states. If we can have full converstion between the two mass states, we can have full conversion between flavor states.

A Unitary Transformation

Suppose the wave function in this basis is written as

(ψ1ψ2).

To remove the position dependent σ3 term in the Hamiltonian which prevents us from solving the equation of motion easily, we define a new basis {|ν~L,|ν~H} where the wave function is related to background matter basis through

(ψ1ψ2)=(eiη(x)00eiη(x))(ψb1ψb2).

Transformation of Pauli Matrices

This transformation, defined as T, is unitary,

TT=I.

It doesn’t change σ3.

Tσ3T=σ3Tσ3T=σ3.

It adds a phase to the off-diagonal elements of σ1,

Tσ1T=(0e2iηe2iη0)Tσ1T=(0e2iηe2iη0).

We can also look at the following very general transformation.

(eiη100eiη1)(a11a12a21a22)(eiη200eiη2)=(a11ei(η1+η2)a12ei(η1η2)a21ei(η1η2)a22ei(η1+η2))

Another very useful relation is

iTxT=xη(x)σ3.

The Schrodinger equation in background matter basis is

iddx(ψ1ψ2)=(ωm2σ3+δλ2cos2θmσ3δλ2sin2θmσ1)(ψ1ψ2)

To write down the Schodinger equation in the new basis, we need the transformation of the Hamiltonian

TLHS=T[i(idηdxeiη00idηdxeiη)(ψb1ψb2)+i(eiη00eiη)ddx(ψ1ψ2)]=i(idηdx00idηdx)(ψb1ψb2)+iddx(ψ1ψ2).
TRHS=[ωm2Tσ3T+δλ2cos2θmTσ3Tδλ2sin2θmTσ1T](ψb1ψb2)=[ωm2σ3+δλ2cos2θmσ3δλ2sin2θm(0e2iηe2iη0)](ψb1ψb2).

The equation of motion in this new basis becomes

(dηdx00dηdx)(ψb1ψb2)+iddx(ψb1ψb2)=[ωm2σ3+δλ2cos2θmσ3δλ2sin2θm(0e2iηe2iη0)](ψb1ψb2)

The key is to remove the σ3 terms using this transformation, which requires

(dηdx00dηdx)(ψb1ψb2)=[ωm2σ3+δλ2cos2θmσ3](ψb1ψb2).

It reduces to

dη(x)dx=ωm2+δλ(x)2cos2θm,

which has a general solution of the form

(1.5)η(x)η(0)=ωm2x+cos2θm20xδλ(τ)dτ.

We might choose η(0)=0, which simplifies the relation

η(x)=ωm2x+cos2θm20xδλ(τ)dτ.

What is left in the equation of motion is the part where off-diagonal Hamiltonian takes effect,

iddx(ψb1ψb2)=δλ2sin2θm(0e2iηe2iη0)(ψb1ψb2).

Other Initial Conditions

The initial condition can be other convinient ones. For example we can remove the integration constant of the last term in the relation.

At any position/time, the wave function in background matter basis is

(1.6)(ψ1(x)ψ2(x))=(eiηψb1(x)eiηψb2(x)).

To calculated the transition from low energy state to high energy state in background matter basis, with initial condition

(ψ1(0)ψ2(0))=(10),

we simply calculate

P12(x)=|eiηψb2(x)|2=|ψb2(x)|2.
  1. Patton, K. M., Kneller, J. P., & McLaughlin, G. C. (2014). Stimulated neutrino transformation through turbulence. Physical Review D, 89(7), 073022. doi:10.1103/PhysRevD.89.073022

  2. Kneller, J. P., McLaughlin, G. C., & Patton, K. M. (2013). Stimulated neutrino transformation in supernovae. AIP Conference Proceedings, 1560, 176–178. doi:10.1063/1.4826746


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